This is the 3rd (obviously) part of the September Random Puzzle. It’s going to be simple, and then take you to the end! Yes, I was feeling a bit lazy.
This is the 2nd part of what I hope will be a month long puzzle of codes and ciphers. See the first before trying this, unless you can crack running key ciphers without any hints.
This part of the puzzle only has two… I could say parts, or I could say puzzles. Which is worse?
Keyword ciphers are fun. Most treasure-hunt riddles are. Running key ciphers are a nightmare to manually crack without the key.
I don’t think that this actually counts as a cipher, but it might be that it doesn’t count as a code. Possibly both. You decide.
I use this as a very quick way to disguise words. Don’t ask why or what sort. It is very easy to write and read on the fly. I just want to see if you need to know how it works to figure it out. I came up with it myself, but it isn’t at all original. Try it.
I made this because I was bored. You’re reading this because you’re bored. Remember that and forgive me for this.
This is pretty simple alphabet based code with no purposeful message, punctuation is not coded
SOLVE THESE CIPHERS:
EACH SENTENCE IS IN A DIFFERENT CODE. THERE ARE 6 SENTANCES.
YOU CAN SOLVE IT ANY WAY YOU WANT, BUT THIS CLUE MAY HELP YOU.
YOUR CLUE : MARLETT, WINGDINGS AND 7 SHELF SYMBOLS ARE SYMBOLS OF WORDS
ANSWER ONE SENTANCE AND GET A CLUE TO ANOTHER.
I HAVE MADE ADJACENT WORDS DIFFERENT COLOURS TO HELP YOU TO SEE THE DIFFERENCE, AND ONE IN EACH PAIR OF SIMILAR SYMBOLS BLUE.
After 5 people have shared in the comments that they’ve solved it, I’ll give an extra clue.
–•• — —• •••
•– •–• •
– •••• •
–••• • ••• –
J.P * = ◊
0.RJ * = ◊
T.E * = ◊
0.IT * = ◊
R.U * = ◊
0.JR * = ◊
note that in 0.JR, 0.IT AND 0.JR, the first digit is a zero (0), not O.
* = x 10/ 100
each pair of ◊s (1st+2nd, 3rd+4th, 5th+6th) = 100
each letter= 1 digit i.e. A=6, ( now no other letter can be 6)
no letter is 0 or 5
How many solutions can you find?
Arrange the letters to make the name of a planet. Find the solution which gives the planet’s name the highest value.
Leave the answers in the comments.